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Question-68079




Question Number 68079 by azizullah last updated on 04/Sep/19
Answered by Rasheed.Sindhi last updated on 07/Sep/19
 ((,(son′s age),(father′s age)),((Now),(          x),(      x+36)),((10 years ago),(      x−10),(      x+26)) )         x+26=3(x−10)      x+26=3x−30)     2x=26+30=56             x=28 (Son′s age now)    x+36=28+36=64(Father′s age now)
$$\begin{pmatrix}{}&{\mathrm{son}'\mathrm{s}\:\mathrm{age}}&{\mathrm{father}'\mathrm{s}\:\mathrm{age}}\\{\mathrm{Now}}&{\:\:\:\:\:\:\:\:\:\:\mathrm{x}}&{\:\:\:\:\:\:\mathrm{x}+\mathrm{36}}\\{\mathrm{10}\:\mathrm{years}\:\mathrm{ago}}&{\:\:\:\:\:\:\mathrm{x}−\mathrm{10}}&{\:\:\:\:\:\:\mathrm{x}+\mathrm{26}}\end{pmatrix}\: \\ $$$$ \\ $$$$\:\:\:\:\mathrm{x}+\mathrm{26}=\mathrm{3}\left(\mathrm{x}−\mathrm{10}\right) \\ $$$$\left.\:\:\:\:\mathrm{x}+\mathrm{26}=\mathrm{3x}−\mathrm{30}\right) \\ $$$$\:\:\:\mathrm{2x}=\mathrm{26}+\mathrm{30}=\mathrm{56} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}=\mathrm{28}\:\left(\mathrm{Son}'\mathrm{s}\:\mathrm{age}\:\mathrm{now}\right) \\ $$$$\:\:\mathrm{x}+\mathrm{36}=\mathrm{28}+\mathrm{36}=\mathrm{64}\left(\mathrm{Father}'\mathrm{s}\:\mathrm{age}\:\mathrm{now}\right) \\ $$

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