Question-68710

Question Number 68710 by peter frank last updated on 15/Sep/19

Commented by Prithwish sen last updated on 15/Sep/19

x + y = 0 \dots \dots . (i)

x - y = - 4 \dots \dots (ii)

solving x = - 2, y = 2

∴ the center of the circle is (- 2, 2)

∴ the radius =∣ \frac{- 2 - 2}{\sqrt{2}} ∣= 2 \sqrt{2} ∵ the radius is perpendicular to the tangent

∴ the equation of cicle

{(x + 2)}^{2} + {(y - 2)}^{2} = {(2 \sqrt{2})}^{2}

x^{2} + y^{2} + 4 x - 4 y = 0

please check .

Commented by peter frank last updated on 15/Sep/19

c o r r e c t s i r

Commented by peter frank last updated on 15/Sep/19

h o w a b o u t Q n 2