Question-68714

Question Number 68714 by Learner-123 last updated on 15/Sep/19

Answered by mr W last updated on 15/Sep/19

a c c e l e r a t i o n o f o b j e c t C = \frac{1.2}{2} = 0.6 m / s^{2}

f o r c e i n c a b l e = \frac{1}{2} \times 375 \times \frac{10 + 0.6}{10} = 198.75 N

p o w e r i n p u t = \frac{198.75 \times 0.6}{0.85} = 140.3 w a t t

Commented by Learner-123 last updated on 15/Sep/19

p l e a s e e l a b o r a t e “ f o r c e i n {c a b l e}^{″} .

Commented by mr W last updated on 16/Sep/19

w e i g h t o f o b j e c t = 375 N

m a s s o f o b j e c t = \frac{375}{g} = 37.5 k g

l e t f o r c e i n c a b l e = T

2 T - m g = m a

\Rightarrow T = \frac{m (g + a)}{2} = \frac{375 (10 + 0.6)}{2 \times 10} = 198.75 N

Commented by Learner-123 last updated on 18/Sep/19

t h a n k s s i r .