Question-68946

Question Number 68946 by ramirez105 last updated on 17/Sep/19

Commented by kaivan.ahmadi last updated on 17/Sep/19

\frac{\partial u}{\partial x} = (2 x y - t a n y) \Rightarrow u (x, y) = x^{2} y - x t a n y + h (y)

\frac{\partial u}{\partial y} = x^{2} - {x s e c}^{2} y = x^{2} - {x s e c}^{2} y + \frac{d h}{d y} \Rightarrow \frac{d h}{d y} = 0 \Rightarrow h = c^{'}

u (x, y) = c \Rightarrow x^{2} y - x t a n y = c