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Question-70997




Question Number 70997 by A8;15: last updated on 10/Oct/19
Answered by MJS last updated on 10/Oct/19
trying first  for an easy solution both a+24 and a+12  must be square numbers  ⇒ a=−8 ⇒ x=−2
$$\mathrm{trying}\:\mathrm{first} \\ $$$$\mathrm{for}\:\mathrm{an}\:\mathrm{easy}\:\mathrm{solution}\:\mathrm{both}\:{a}+\mathrm{24}\:\mathrm{and}\:{a}+\mathrm{12} \\ $$$$\mathrm{must}\:\mathrm{be}\:\mathrm{square}\:\mathrm{numbers} \\ $$$$\Rightarrow\:{a}=−\mathrm{8}\:\Rightarrow\:{x}=−\mathrm{2} \\ $$

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