Question Number 7164 by aftab ahmad last updated on 14/Aug/16
Answered by Yozzia last updated on 14/Aug/16
$${By}\:{Power}\:{of}\:{a}\:{Point}\:{theorem}, \\ $$$$\left({AB}\right)\left({AC}\right)=\left({AD}\right)\left({AD}\right)=\left({AD}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{AC}=\frac{\left({AD}\right)^{\mathrm{2}} }{{AB}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{5}}=\mathrm{20}{cm} \\ $$
Commented by aftab ahmad last updated on 14/Aug/16
$$\boldsymbol{{T}}{hank}\:{you}\:\boldsymbol{{so}}\:\boldsymbol{{much}}\:\boldsymbol{{sir}}\:\boldsymbol{{for}}\:\boldsymbol{{the}}\:\boldsymbol{{help}}. \\ $$