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Question-71693




Question Number 71693 by TawaTawa last updated on 18/Oct/19
Answered by MJS last updated on 19/Oct/19
the discs are cylinders  V=πr^2 h  V=π×1^2 ×1+π×2^2 ×1+π×3^2 ×1=14π  h=(V/(πr^2 ))=((14π)/(π×1^2 ))=14
$$\mathrm{the}\:\mathrm{discs}\:\mathrm{are}\:\mathrm{cylinders} \\ $$$${V}=\pi{r}^{\mathrm{2}} {h} \\ $$$${V}=\pi×\mathrm{1}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{2}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{3}^{\mathrm{2}} ×\mathrm{1}=\mathrm{14}\pi \\ $$$${h}=\frac{{V}}{\pi{r}^{\mathrm{2}} }=\frac{\mathrm{14}\pi}{\pi×\mathrm{1}^{\mathrm{2}} }=\mathrm{14} \\ $$
Commented by TawaTawa last updated on 19/Oct/19
God bless you sir
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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