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Question-71790




Question Number 71790 by jatin123 last updated on 20/Oct/19
Answered by $@ty@m123 last updated on 20/Oct/19
=(2/3)×(3/4)×.....×((98)/(99))×((99)/(100))  =(2/(100))=(1/(50))
$$=\frac{\mathrm{2}}{\mathrm{3}}×\frac{\mathrm{3}}{\mathrm{4}}×…..×\frac{\mathrm{98}}{\mathrm{99}}×\frac{\mathrm{99}}{\mathrm{100}} \\ $$$$=\frac{\mathrm{2}}{\mathrm{100}}=\frac{\mathrm{1}}{\mathrm{50}} \\ $$
Commented by jatin123 last updated on 20/Oct/19
can u please slove kt step by step
$$\mathrm{can}\:\mathrm{u}\:\mathrm{please}\:\mathrm{slove}\:\mathrm{kt}\:\mathrm{step}\:\mathrm{by}\:\mathrm{step}\: \\ $$
Commented by mr W last updated on 20/Oct/19
1−(1/3)=(2/3)  1−(1/4)=(3/4)  1−(1/5)=(4/5)  ......  1−(1/(100))=((99)/(100))
$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$$…… \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{100}}=\frac{\mathrm{99}}{\mathrm{100}} \\ $$

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