Question-71946

Question Number 71946 by oyemi kemewari last updated on 22/Oct/19

Answered by MJS last updated on 23/Oct/19

12 = 3 y {(\frac{3 y}{3 + 3 y})}^{2 / 3} {(\frac{1}{400})}^{1 / 2}

80 = y {(\frac{y}{y + 1})}^{2 / 3}

512000 = y^{3} \frac{y^{2}}{{(y + 1)}^{2}}

y^{5} - 512000 y^{2} - 1024000 y - 512000 = 0

\Rightarrow y \approx 80.6599

Commented by oyemi kemewari last updated on 25/Oct/19

thanks sir

Commented by oyemi kemewari last updated on 25/Oct/19

but how did you get y from line 4

Commented by MJS last updated on 26/Oct/19

we can only approximate

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