Question Number 72414 by aliesam last updated on 28/Oct/19
Commented by aliesam last updated on 28/Oct/19
$${a},{b}\:{and}\:{d}\:{are}\:{centres}\:{of}\:{three}\:{circles}\: \\ $$$${find}\: \\ $$$$\frac{{AC}}{{AB}} \\ $$
Answered by mr W last updated on 28/Oct/19
$${let}\:{AC}={a},\:{AB}={BD}={b} \\ $$$${a}\:\mathrm{sin}\:\mathrm{30}°={b}\:\mathrm{sin}\:\mathrm{60}° \\ $$$$\frac{{AC}}{{AB}}=\frac{{a}}{{b}}=\frac{\mathrm{sin}\:\mathrm{60}°}{\mathrm{sin}\:\mathrm{30}°}=\sqrt{\mathrm{3}} \\ $$
Commented by aliesam last updated on 28/Oct/19
$${god}\:{bless}\:{you}\:{sir} \\ $$
Commented by mr W last updated on 28/Oct/19