Question-72414

Question Number 72414 by aliesam last updated on 28/Oct/19

Commented by aliesam last updated on 28/Oct/19

a, b a n d d a r e c e n t r e s o f t h r e e c i r c l e s

f i n d

\frac{A C}{A B}

Answered by mr W last updated on 28/Oct/19

l e t A C = a, A B = B D = b

a \sin 30 ° = b \sin 60 °

\frac{A C}{A B} = \frac{a}{b} = \frac{\sin 60 °}{\sin 30 °} = \sqrt{3}

Commented by aliesam last updated on 28/Oct/19

g o d b l e s s y o u s i r

Commented by mr W last updated on 28/Oct/19

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