Menu Close

Question-72421

Tinku Tara 0 Comments
Pin




Question Number 72421 by TawaTawa last updated on 28/Oct/19
Answered by mind is power last updated on 28/Oct/19
let a,b,c,d root[in C a+b+c+d=−2 a+b=2 c+d=−4 ab+ac+ad+bc+bd+cd=2..s (a+b)(c+d)=ac+ad+bc+bd=2.−4=−8 ⇒s⇔ab+cd=10 abcd=25=ab.cd ab,cd root of X^2 −10X+25=0 ab=cd=5,a+b=2,c+d=−4 a,b root of x^2 −2x+5=0 ⇒(a,b)∈{(1−2i,1+2i),(1+2i,1−2i)} (c,d)roots of x^2 +4x+5=0 (c,d)∈{−2+i,−2−i} roots are 1+_− 2i,−2+_− i
leta,b,c,droot[inCa+b+c+d=−2a+b=2c+d=−4ab+ac+ad+bc+bd+cd=2..s(a+b)(c+d)=ac+ad+bc+bd=2.−4=−8⇒s⇔ab+cd=10abcd=25=ab.cdab,cdrootofX2−10X+25=0ab=cd=5,a+b=2,c+d=−4a,brootofx2−2x+5=0⇒(a,b)∈{(1−2i,1+2i),(1+2i,1−2i)}(c,d)rootsofx2+4x+5=0(c,d)∈{−2+i,−2−i}rootsare1+−2i,−2+−i
Commented by TawaTawa last updated on 28/Oct/19
God bless you sir
Godblessyousir
Commented by mind is power last updated on 28/Oct/19
y,re welcom
y,rewelcom

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *