Menu Close

Question-73111




Question Number 73111 by oyemi kemewari last updated on 06/Nov/19
Answered by mr W last updated on 07/Nov/19
5=(1/2)gt^2   ⇒t=10 s  horizontal distance =0.8×10=8 m
$$\mathrm{5}=\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} \\ $$$$\Rightarrow{t}=\mathrm{10}\:{s} \\ $$$${horizontal}\:{distance}\:=\mathrm{0}.\mathrm{8}×\mathrm{10}=\mathrm{8}\:{m}\: \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *