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Question-73203




Question Number 73203 by Tanmay chaudhury last updated on 08/Nov/19
Commented by kaivan.ahmadi last updated on 08/Nov/19
xsin(1/x)=1⇒sin(1/x)=(1/x)⇒(1/x)=0⇒there is no root  so A has exactly one element, A={0}
$${xsin}\frac{\mathrm{1}}{{x}}=\mathrm{1}\Rightarrow{sin}\frac{\mathrm{1}}{{x}}=\frac{\mathrm{1}}{{x}}\Rightarrow\frac{\mathrm{1}}{{x}}=\mathrm{0}\Rightarrow{there}\:{is}\:{no}\:{root} \\ $$$${so}\:{A}\:{has}\:{exactly}\:{one}\:{element},\:{A}=\left\{\mathrm{0}\right\} \\ $$

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