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Question-73260




Question Number 73260 by Lontum Hans last updated on 09/Nov/19
Answered by mr W last updated on 09/Nov/19
T_(max) =m((v^2 /r)+g)=8((6^2 /2)+10)=224 N  T_(min) =m((v^2 /r)−g)=8((6^2 /2)−10)=64 N
$${T}_{{max}} ={m}\left(\frac{{v}^{\mathrm{2}} }{{r}}+{g}\right)=\mathrm{8}\left(\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}+\mathrm{10}\right)=\mathrm{224}\:{N} \\ $$$${T}_{{min}} ={m}\left(\frac{{v}^{\mathrm{2}} }{{r}}−{g}\right)=\mathrm{8}\left(\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}−\mathrm{10}\right)=\mathrm{64}\:{N} \\ $$
Commented by Lontum Hans last updated on 09/Nov/19
nNot accurate
$$\mathrm{nN}{ot}\:{accurate} \\ $$

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