Question Number 73910 by Rio Michael last updated on 16/Nov/19
Commented by Rio Michael last updated on 16/Nov/19
$${given}\:{figure}\:\mathrm{1}. \\ $$$${in}\:{which}\:{direction}\:{will}\:{the}\:{reaction}\:{of}\:{at}\:{the} \\ $$$${hinge}\:{be}\:{inclined}. \\ $$$${is}\:{it}\:{to}\:{the}\:{vertical}\:{or}\:{horizontal}? \\ $$$$ \\ $$
Commented by mr W last updated on 16/Nov/19
Commented by Rio Michael last updated on 16/Nov/19
$${thanks}\:{sir},{where}\:{do}\:{i}\:{place}\:{the}\:{angle}\:\theta\:{for}\:{the}\: \\ $$$${Reaction}\:{at}\:{the}\:{hinge} \\ $$
Commented by mr W last updated on 16/Nov/19
$$\mathrm{tan}\:\theta=\frac{\frac{{L}}{\mathrm{4}}×\mathrm{tan}\:\mathrm{40}°}{{L}}=\frac{\mathrm{tan}\:\mathrm{40}°}{\mathrm{4}} \\ $$$$\Rightarrow\theta=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{tan}\:\mathrm{40}°}{\mathrm{4}}\right)=\mathrm{11}.\mathrm{85}° \\ $$
Commented by mr W last updated on 16/Nov/19
Commented by Rio Michael last updated on 16/Nov/19
$${thank}\:{you}\:{sir} \\ $$