Question Number 74112 by TawaTawa last updated on 19/Nov/19
Answered by mind is power last updated on 19/Nov/19
$${let}\:{l}={side}\:{of}\:{squar}\Rightarrow{l}^{\mathrm{2}} +\frac{{l}}{\mathrm{2}}\left({x}+{z}+{y}\right)=\frac{\left({z}+{l}+{y}\right)}{\mathrm{2}}\left({l}+{x}\right) \\ $$$$\Leftrightarrow\mathrm{2}{l}^{\mathrm{2}} +{l}\left({x}+{y}+{z}\right)={l}\left({z}+{y}+{l}\right)+{x}\left({z}+{l}+{y}\right) \\ $$$$\Rightarrow\mathrm{2}{l}^{\mathrm{2}} +{l}\left({x}+{y}+{z}\right)={l}\left({x}+{y}+{z}\right)+{l}^{\mathrm{2}} +{xz}+{xy} \\ $$$$\Leftrightarrow{l}^{\mathrm{2}} ={x}\left({z}+{y}\right)={area} \\ $$$$ \\ $$
Commented by TawaTawa last updated on 19/Nov/19
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$