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Question-74141




Question Number 74141 by MASANJAJ last updated on 19/Nov/19
Commented by TawaTawa last updated on 19/Nov/19
d)                 a  =  5             Forth term  =   ar^3   =  40         ∴       5r^3   =  40         ∴       r^3   =  ((40)/5)         ∴       r^3   =  8         ∴       r^3   =  2^3          ∴       r  =  2  ∴       x   =   second term  = ar   =   5 × 2  =  10  ∴       y   =   third term  = ar^2    =   5 × 2^2   =  5 × 4  =  20
$$\left.\mathrm{d}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\:\:=\:\:\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{Forth}\:\mathrm{term}\:\:=\:\:\:\mathrm{ar}^{\mathrm{3}} \:\:=\:\:\mathrm{40} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{5r}^{\mathrm{3}} \:\:=\:\:\mathrm{40} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{r}^{\mathrm{3}} \:\:=\:\:\frac{\mathrm{40}}{\mathrm{5}} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{r}^{\mathrm{3}} \:\:=\:\:\mathrm{8} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{r}^{\mathrm{3}} \:\:=\:\:\mathrm{2}^{\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{r}\:\:=\:\:\mathrm{2} \\ $$$$\therefore\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{second}\:\mathrm{term}\:\:=\:\mathrm{ar}\:\:\:=\:\:\:\mathrm{5}\:×\:\mathrm{2}\:\:=\:\:\mathrm{10} \\ $$$$\therefore\:\:\:\:\:\:\:\mathrm{y}\:\:\:=\:\:\:\mathrm{third}\:\mathrm{term}\:\:=\:\mathrm{ar}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{5}\:×\:\mathrm{2}^{\mathrm{2}} \:\:=\:\:\mathrm{5}\:×\:\mathrm{4}\:\:=\:\:\mathrm{20} \\ $$

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