Question Number 74429 by azizullah last updated on 24/Nov/19
Commented by MJS last updated on 24/Nov/19
$$\mathrm{perimeter}=\mathrm{4}×\sqrt{\mathrm{area}} \\ $$$$\mathrm{118m}^{\mathrm{2}} +\mathrm{81dm}^{\mathrm{2}} =\mathrm{11881dm}^{\mathrm{2}} \\ $$$${p}=\mathrm{4}×\sqrt{\mathrm{11881dm}^{\mathrm{2}} }=\mathrm{4}×\mathrm{109dm}=\mathrm{436dm}= \\ $$$$=\mathrm{43m}\:\mathrm{6dm} \\ $$
Commented by azizullah last updated on 24/Nov/19
$$\mathrm{thanks}\:\mathrm{sir} \\ $$