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Question-74429




Question Number 74429 by azizullah last updated on 24/Nov/19
Commented by MJS last updated on 24/Nov/19
perimeter=4×(√(area))  118m^2 +81dm^2 =11881dm^2   p=4×(√(11881dm^2 ))=4×109dm=436dm=  =43m 6dm
$$\mathrm{perimeter}=\mathrm{4}×\sqrt{\mathrm{area}} \\ $$$$\mathrm{118m}^{\mathrm{2}} +\mathrm{81dm}^{\mathrm{2}} =\mathrm{11881dm}^{\mathrm{2}} \\ $$$${p}=\mathrm{4}×\sqrt{\mathrm{11881dm}^{\mathrm{2}} }=\mathrm{4}×\mathrm{109dm}=\mathrm{436dm}= \\ $$$$=\mathrm{43m}\:\mathrm{6dm} \\ $$
Commented by azizullah last updated on 24/Nov/19
thanks sir
$$\mathrm{thanks}\:\mathrm{sir} \\ $$

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