Question Number 74634 by Mr. K last updated on 27/Nov/19
Commented by Mr. K last updated on 28/Nov/19
$${The}\:{square}\:{is}\:{divided}\:{into}\:\mathrm{2}\:{triangles} \\ $$$${and}\:{one}\:{quadrilateral}.\:{The}\:{yellow} \\ $$$${area}\:{is}\:{S}\:{and}\:{the}\:{blue}\:{area}\:{is}\:\:\frac{{S}}{\mathrm{2}}. \\ $$$${Find}\:{AB}. \\ $$
Commented by Mr. K last updated on 28/Nov/19
$${I}\:{find}\:\:\frac{\mathrm{19}}{\mathrm{3}},\:{is}\:{this}\:{right}? \\ $$
Commented by Mr. K last updated on 28/Nov/19
Commented by Mr. K last updated on 28/Nov/19
$$\frac{\frac{\mathrm{4}}{\mathrm{3}}}{\mathrm{8}}=\frac{{x}}{\mathrm{2}}\Rightarrow{x}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$${y}={x}+\mathrm{6}\Rightarrow{y}=\frac{\mathrm{19}}{\mathrm{3}} \\ $$$${Is}\:{this}\:{right}\:{or}\:{are}\:{the}\:{triangles} \\ $$$${DEF}\:{and}\:{DGH}\:{are}\:{not}\:{similar}? \\ $$$$\: \\ $$
Commented by Mr. K last updated on 28/Nov/19
$${This}\:{answer}\:{is}\:{not}\:{among}\:{the} \\ $$$${alternatives}. \\ $$
Commented by MJS last updated on 28/Nov/19
$$\mathrm{you}\:\mathrm{are}\:\mathrm{right},\:\frac{\mathrm{19}}{\mathrm{3}}\:\mathrm{is}\:\mathrm{the}\:\mathrm{right}\:\mathrm{answer} \\ $$