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Question-75105




Question Number 75105 by chess1 last updated on 07/Dec/19
Commented by MJS last updated on 07/Dec/19
arctan ((40−4(√2))/(21))
$$\mathrm{arctan}\:\frac{\mathrm{40}−\mathrm{4}\sqrt{\mathrm{2}}}{\mathrm{21}} \\ $$

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