Question Number 75826 by liki last updated on 18/Dec/19
Commented by liki last updated on 18/Dec/19
$$…{plz}\:{help}\:{me}\:{part}\:\left({c}\right). \\ $$
Answered by mr W last updated on 18/Dec/19
$${a}. \\ $$$$\mathrm{4}×\mathrm{6}×\mathrm{6}×\mathrm{6}=\mathrm{864} \\ $$$${b}. \\ $$$$\mathrm{4}×\mathrm{5}×\mathrm{4}×\mathrm{3}=\mathrm{240} \\ $$$${c}. \\ $$$$\mathrm{4}×\mathrm{4}×\mathrm{3}+\mathrm{2}×\mathrm{3}×\mathrm{4}×\mathrm{3}=\mathrm{120} \\ $$$$\:\:\:\uparrow{XYZ}\mathrm{2}\:\:\:\uparrow{XYZ}\left(\mathrm{4}\:{or}\:\mathrm{6}\right) \\ $$
Commented by liki last updated on 18/Dec/19
$$..\boldsymbol{{Thank}}\:\boldsymbol{{you}}\:\boldsymbol{{sir}},\:\boldsymbol{{be}}\:\boldsymbol{{blessed}}. \\ $$