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Question-75879




Question Number 75879 by TawaTawa last updated on 19/Dec/19
Answered by mr W last updated on 19/Dec/19
Commented by mr W last updated on 19/Dec/19
T_1 =T_2 =mg=100×10=1000 N  F=2T_1 cos 30°=2×1000×((√3)/2)=1732 N
$${T}_{\mathrm{1}} ={T}_{\mathrm{2}} ={mg}=\mathrm{100}×\mathrm{10}=\mathrm{1000}\:{N} \\ $$$${F}=\mathrm{2}{T}_{\mathrm{1}} \mathrm{cos}\:\mathrm{30}°=\mathrm{2}×\mathrm{1000}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}=\mathrm{1732}\:{N} \\ $$
Commented by TawaTawa last updated on 19/Dec/19
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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