Question Number 75991 by Ajao yinka last updated on 21/Dec/19
Commented by mivheal last updated on 22/Dec/19
$${no}\:{answer} \\ $$
Answered by mind is power last updated on 22/Dec/19
$$\int_{\mathrm{0}} ^{\mathrm{1}} \:\mathrm{or}\:\int_{\mathrm{1}} ^{+\infty} \:\: \\ $$$$\int_{\mathrm{0}} ^{+\infty} \:\:\mathrm{fonction}\:\mathrm{not}\:\mathrm{defind}\:\mathrm{at}\:\mathrm{x}=\mathrm{1} \\ $$