Question-76645

Question Number 76645 by naka3546 last updated on 29/Dec/19

Commented by mr W last updated on 29/Dec/19

{(5 - a)}^{2} = a^{2} + {(3 + a)}^{2}

a^{2} + 16 a - 16 = 0

\Rightarrow a = 4 \sqrt{5} - 8 = 2 (2 \sqrt{5} - 4)

{(a + b)}^{2} = a^{2} + {(2 - a)}^{2}

\Rightarrow b = \sqrt{a^{2} + {(2 - a)}^{2}} - a = 6 (\sqrt{5} - 2) - 4 \sqrt{5} + 8 = 2 \sqrt{5} - 4

\Rightarrow \frac{a}{b} = \frac{2 (2 \sqrt{5} - 4)}{2 \sqrt{5} - 4} = 2

Answered by benjo 1/2 santuyy last updated on 29/Dec/19