Question-76826

Question Number 76826 by Master last updated on 30/Dec/19

Answered by john santu last updated on 31/Dec/19

= \int \underset{0}{\overset{2}{}} \int \underset{0}{\overset{1}{}} \int \underset{0}{\overset{3}{}} (2 y + z + x) d z d y d x

= \int \underset{0}{\overset{2}{}} \int \underset{0}{\overset{1}{}} (2 y z + \frac{1}{2} z^{2} + x z) \underset{0}{\overset{3}{∣}} d y d x

= \int \underset{0}{\overset{2}{}} \int \underset{0}{\overset{1}{}} (6 y + \frac{9}{2} + 3 x) d y d x

= \underset{0}{\int^{2}} (3 y^{2} + 3 x y + \frac{9}{2} y) ∣ \underset{0}{\overset{1}{}} d x

= \underset{0}{\int^{2}} (\frac{15}{2} + 3 x) d x = \frac{15}{2} x + \frac{3}{2} x^{2} \underset{0}{\overset{2}{∣}}

= 15 + 6 = 21 . (d o n e) .

Commented by Master last updated on 31/Dec/19

thanks

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