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Question-7803




Question Number 7803 by Tawakalitu. last updated on 16/Sep/16
Answered by Rasheed Soomro last updated on 16/Sep/16
(((1×3×5×...×2015)/(2×4×6×...×2016)))^(1/4)   (((2015!/(2.4.6.....2014)/(2.4.6.....2016)))^(1/4)   (((2015!)/((2.4.6....2014)(2.4.6.....2016))))^(1/4)   (((2015!)/((2.4.6....2014)^2 (2015.2016))))^(1/4)   (((2015!)/(2^(2014) (1.2.3....1007)^2 (2015.1008.2))))^(1/4)   (((2015!)/(2^(2015) (1007!)^2 (2015.1008))))^(1/4)   (((2014!)/(2^(2015) (1008!)(1007!))))^(1/4)
$$\left(\frac{\mathrm{1}×\mathrm{3}×\mathrm{5}×…×\mathrm{2015}}{\mathrm{2}×\mathrm{4}×\mathrm{6}×…×\mathrm{2016}}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2015}!/\left(\mathrm{2}.\mathrm{4}.\mathrm{6}…..\mathrm{2014}\right.}{\mathrm{2}.\mathrm{4}.\mathrm{6}…..\mathrm{2016}}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2015}!}{\left(\mathrm{2}.\mathrm{4}.\mathrm{6}….\mathrm{2014}\right)\left(\mathrm{2}.\mathrm{4}.\mathrm{6}…..\mathrm{2016}\right)}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2015}!}{\left(\mathrm{2}.\mathrm{4}.\mathrm{6}….\mathrm{2014}\right)^{\mathrm{2}} \left(\mathrm{2015}.\mathrm{2016}\right)}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2015}!}{\mathrm{2}^{\mathrm{2014}} \left(\mathrm{1}.\mathrm{2}.\mathrm{3}….\mathrm{1007}\right)^{\mathrm{2}} \left(\mathrm{2015}.\mathrm{1008}.\mathrm{2}\right)}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2015}!}{\mathrm{2}^{\mathrm{2015}} \left(\mathrm{1007}!\right)^{\mathrm{2}} \left(\mathrm{2015}.\mathrm{1008}\right)}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$\left(\frac{\mathrm{2014}!}{\mathrm{2}^{\mathrm{2015}} \left(\mathrm{1008}!\right)\left(\mathrm{1007}!\right)}\right)^{\mathrm{1}/\mathrm{4}} \\ $$$$ \\ $$
Commented by Tawakalitu. last updated on 16/Sep/16
Thanks so much sir. is that all ?
$${Thanks}\:{so}\:{much}\:{sir}.\:{is}\:{that}\:{all}\:? \\ $$
Commented by Tawakalitu. last updated on 16/Sep/16
Thanks so much sir. is that all ?
$${Thanks}\:{so}\:{much}\:{sir}.\:{is}\:{that}\:{all}\:? \\ $$

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