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Question-78309




Question Number 78309 by otchereabdullai@gmail.com last updated on 15/Jan/20
Answered by mind is power last updated on 15/Jan/20
∠BAO=∠OBA=90−x  ∠BOA=180−∠ABO−∠OAB=180−(90−x+90−x)=2x
$$\angle\mathrm{BAO}=\angle\mathrm{OBA}=\mathrm{90}−\mathrm{x} \\ $$$$\angle\mathrm{BOA}=\mathrm{180}−\angle\mathrm{ABO}−\angle\mathrm{OAB}=\mathrm{180}−\left(\mathrm{90}−\mathrm{x}+\mathrm{90}−\mathrm{x}\right)=\mathrm{2x} \\ $$$$ \\ $$
Commented by otchereabdullai@gmail.com last updated on 16/Jan/20
thank you sir power
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir}\:\mathrm{power} \\ $$

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