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Question-8269




Question Number 8269 by tawakalitu last updated on 04/Oct/16
Commented by tawakalitu last updated on 04/Oct/16
Find x and y. thanks in advance.
$$\mathrm{Find}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}.\:\mathrm{thanks}\:\mathrm{in}\:\mathrm{advance}. \\ $$
Answered by prakash jain last updated on 05/Oct/16
x+y=(√2)cos 45=(√2)×(1/( (√2)))=1  Perpendicular line on right side  xtan 60=(√2)sin 45⇒x=(1/(tan 60))=(1/( (√3)))  y=1−(1/( (√3)))=(((√3)−1)/( (√3)))
$${x}+{y}=\sqrt{\mathrm{2}}\mathrm{cos}\:\mathrm{45}=\sqrt{\mathrm{2}}×\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}=\mathrm{1} \\ $$$$\mathrm{Perpendicular}\:\mathrm{line}\:\mathrm{on}\:\mathrm{right}\:\mathrm{side} \\ $$$${x}\mathrm{tan}\:\mathrm{60}=\sqrt{\mathrm{2}}\mathrm{sin}\:\mathrm{45}\Rightarrow{x}=\frac{\mathrm{1}}{\mathrm{tan}\:\mathrm{60}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}} \\ $$$${y}=\mathrm{1}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}=\frac{\sqrt{\mathrm{3}}−\mathrm{1}}{\:\sqrt{\mathrm{3}}} \\ $$
Commented by tawakalitu last updated on 05/Oct/16
Thanks for your help.
$$\mathrm{Thanks}\:\mathrm{for}\:\mathrm{your}\:\mathrm{help}. \\ $$

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