Question Number 8300 by tawakalitu last updated on 06/Oct/16
Commented by ridwan balatif last updated on 07/Oct/16
$$\mathrm{solution} \\ $$$$\mathrm{1}.{v}=\sqrt{\mathrm{2gh}},\:\mathrm{where}\:\mathrm{h}\:\mathrm{is}\:\mathrm{height}\:\mathrm{and}\:\mathrm{g}\:\mathrm{is}\:\mathrm{gravitational}\:\mathrm{acceleration} \\ $$$$\:\:\:\:{v}=\sqrt{\mathrm{2}×\mathrm{9}.\mathrm{8}×\mathrm{5}} \\ $$$$\:\:\:\:{v}=\mathrm{9}.\mathrm{899}\:{m}/{s} \\ $$$$\:\:\:\:\:{t}=\sqrt{\frac{\mathrm{2}{h}}{{g}}} \\ $$$$\:\:\:\:\:{t}=\sqrt{\frac{\mathrm{2}×\mathrm{5}}{\mathrm{9}.\mathrm{8}}} \\ $$$$\:\:\:\:\:{t}=\mathrm{1}.\mathrm{01}\:{s} \\ $$
Commented by tawakalitu last updated on 07/Oct/16
$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort}. \\ $$