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Question-8300




Question Number 8300 by tawakalitu last updated on 06/Oct/16
Commented by ridwan balatif last updated on 07/Oct/16
solution  1.v=(√(2gh)), where h is height and g is gravitational acceleration      v=(√(2×9.8×5))      v=9.899 m/s       t=(√((2h)/g))       t=(√((2×5)/(9.8)))       t=1.01 s
$$\mathrm{solution} \\ $$$$\mathrm{1}.{v}=\sqrt{\mathrm{2gh}},\:\mathrm{where}\:\mathrm{h}\:\mathrm{is}\:\mathrm{height}\:\mathrm{and}\:\mathrm{g}\:\mathrm{is}\:\mathrm{gravitational}\:\mathrm{acceleration} \\ $$$$\:\:\:\:{v}=\sqrt{\mathrm{2}×\mathrm{9}.\mathrm{8}×\mathrm{5}} \\ $$$$\:\:\:\:{v}=\mathrm{9}.\mathrm{899}\:{m}/{s} \\ $$$$\:\:\:\:\:{t}=\sqrt{\frac{\mathrm{2}{h}}{{g}}} \\ $$$$\:\:\:\:\:{t}=\sqrt{\frac{\mathrm{2}×\mathrm{5}}{\mathrm{9}.\mathrm{8}}} \\ $$$$\:\:\:\:\:{t}=\mathrm{1}.\mathrm{01}\:{s} \\ $$
Commented by tawakalitu last updated on 07/Oct/16
I appreciate your effort.
$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort}. \\ $$

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