Question Number 8884 by tawakalitu last updated on 03/Nov/16
Answered by sandy_suhendra last updated on 04/Nov/16
Commented by sandy_suhendra last updated on 04/Nov/16
$$\mathrm{let}\:\mathrm{AL}=\mathrm{the}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{pointA}\:\mathrm{to}\:\mathrm{the}\:\mathrm{lower}\:\mathrm{hill} \\ $$$$\mathrm{and}\:\mathrm{AH}=\mathrm{the}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{pointA}\:\mathrm{to}\:\mathrm{the}\:\mathrm{higher}\:\mathrm{hill} \\ $$$$\mathrm{LH}=\mathrm{the}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{higher}\:\mathrm{hill}\:\mathrm{to}\:\mathrm{the}\:\mathrm{lower}\:\mathrm{hill} \\ $$$$\mathrm{LH}=\sqrt{\mathrm{3000}^{\mathrm{2}} +\mathrm{2000}^{\mathrm{2}} −\mathrm{2}×\mathrm{3000}×\mathrm{2000}×\mathrm{cos120}°} \\ $$$$\:\:\:\:\:\:\:=\mathrm{4358}.\mathrm{9}\:\mathrm{m} \\ $$
Commented by sandy_suhendra last updated on 04/Nov/16
Commented by sandy_suhendra last updated on 04/Nov/16
$$\mathrm{y}_{\mathrm{L}} =\mathrm{the}\:\mathrm{height}\:\mathrm{of}\:\mathrm{the}\:\mathrm{lower}\:\mathrm{hill} \\ $$$$\:\:\:\:=\:\mathrm{3000}×\mathrm{tan2}°=\mathrm{104}.\mathrm{8}\:\mathrm{m} \\ $$$$\mathrm{y}_{\mathrm{H}} =\mathrm{the}\:\mathrm{height}\:\mathrm{of}\:\mathrm{the}\:\mathrm{higher}\:\mathrm{hill} \\ $$$$\:\:=\:\mathrm{2000}×\mathrm{tan5}°\:=\mathrm{175}\:\mathrm{meter} \\ $$
Commented by sandy_suhendra last updated on 04/Nov/16
Commented by sandy_suhendra last updated on 04/Nov/16
$$\mathrm{let}\:\theta=\mathrm{the}\:\mathrm{elevation}\:\mathrm{angle} \\ $$$$\mathrm{tan}\:\theta\:=\:\frac{\mathrm{175}−\mathrm{104}.\mathrm{8}}{\mathrm{4358}.\mathrm{9}} \\ $$$$\:\:\:\:\:\:\:\:\theta\:=\:\mathrm{0}.\mathrm{92}°\:\approx\:\mathrm{1}° \\ $$
Commented by tawakalitu last updated on 04/Nov/16
$$\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}\:.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$