Question Number 8924 by tawakalitu last updated on 05/Nov/16
Commented by tawakalitu last updated on 05/Nov/16
$$\mathrm{From}\:\mathrm{the}\:\mathrm{diagram}\:\mathrm{above}\:,\:\mathrm{find}\:\mathrm{the}\:\mathrm{fraction} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{portion} \\ $$
Commented by Rasheed Soomro last updated on 09/Nov/16
$$\mathrm{Of}\:\mathrm{whole}\:\mathrm{diagram}\:\mathrm{or}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{only}? \\ $$
Answered by sandy_suhendra last updated on 09/Nov/16
Commented by sandy_suhendra last updated on 09/Nov/16
$$\angle\mathrm{ROS}=\angle\mathrm{TOU}=\mathrm{180}°−\mathrm{90}°−\mathrm{60}°=\mathrm{30}° \\ $$$$\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shade}=\frac{\mathrm{30}°+\mathrm{30}°}{\mathrm{360}°}=\frac{\mathrm{1}}{\mathrm{6}} \\ $$
Commented by tawakalitu last updated on 09/Nov/16
$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}.\: \\ $$