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Question-9204




Question Number 9204 by tawakalitu last updated on 23/Nov/16
Answered by mrW last updated on 23/Nov/16
300×9.81×20/60=981 Nm/s  The power rating of the pump:  981/0.80=1226 Watt  The rate of loss of energy is 20%.
$$\mathrm{300}×\mathrm{9}.\mathrm{81}×\mathrm{20}/\mathrm{60}=\mathrm{981}\:\mathrm{Nm}/\mathrm{s} \\ $$$$\mathrm{The}\:\mathrm{power}\:\mathrm{rating}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pump}: \\ $$$$\mathrm{981}/\mathrm{0}.\mathrm{80}=\mathrm{1226}\:\mathrm{Watt} \\ $$$$\mathrm{The}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{loss}\:\mathrm{of}\:\mathrm{energy}\:\mathrm{is}\:\mathrm{20\%}. \\ $$
Commented by tawakalitu last updated on 23/Nov/16
God bless you sir. i really appreciate.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$

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