Question-9404

Tinku Tara June 3, 2023 None 0 Comments

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Question Number 9404 by alfat123 last updated on 05/Dec/16

Answered by geovane10math last updated on 06/Dec/16

I can′t read... f′(x) = 2x + 2 ∫f′(x) dx = ∫ 2x + 2 dx = ∫2x dx + ∫2 dx = x^2 + 2x + C f(x) = x^2 + 2x + C f(2) = 8 + C

I {can}^{'} t read \dots

f^{'} (x) = 2 x + 2

\int f^{'} (x) d x = \int 2 x + 2 d x = \int 2 x d x + \int 2 d x

= x^{2} + 2 x + C

f (x) = x^{2} + 2 x + C

f (2) = 8 + C

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