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Question-9571




Question Number 9571 by PANKAJ last updated on 16/Dec/16
Answered by ridwan balatif last updated on 17/Dec/16
1.((x/3)+1,y−(2/3))=((5/3),(1/3))  (x/3)+1=(5/3)              y−(2/3)=(1/3)          (x/3)=(2/3)                        y=1  x=2  so (x,y)→(2,1)
$$\mathrm{1}.\left(\frac{\mathrm{x}}{\mathrm{3}}+\mathrm{1},\mathrm{y}−\frac{\mathrm{2}}{\mathrm{3}}\right)=\left(\frac{\mathrm{5}}{\mathrm{3}},\frac{\mathrm{1}}{\mathrm{3}}\right) \\ $$$$\frac{\mathrm{x}}{\mathrm{3}}+\mathrm{1}=\frac{\mathrm{5}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}−\frac{\mathrm{2}}{\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{x}}{\mathrm{3}}=\frac{\mathrm{2}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}=\mathrm{1} \\ $$$$\mathrm{x}=\mathrm{2} \\ $$$$\mathrm{so}\:\left(\mathrm{x},\mathrm{y}\right)\rightarrow\left(\mathrm{2},\mathrm{1}\right) \\ $$

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