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Question-9627




Question Number 9627 by ridwan balatif last updated on 21/Dec/16
Commented by ridwan balatif last updated on 21/Dec/16
Commented by sou1618 last updated on 22/Dec/16
△ADE∽△CME  so  AE:CE=AD:CM    AE:(AC−AE)=2:1    AE=2(AC−AE)    AE=(2/3)AC    AE=52 .
ADECMEsoAE:CE=AD:CMAE:(ACAE)=2:1AE=2(ACAE)AE=23ACAE=52.
Answered by mrW last updated on 21/Dec/16
((AE)/(EC))=((AD)/(MC))=(2/1)  AE=2×EC=2×(AC−AE)=2×AC−2×AE  3×AE=2×AC  AE=(2/3)×AC=(2/3)×78=52
AEEC=ADMC=21AE=2×EC=2×(ACAE)=2×AC2×AE3×AE=2×ACAE=23×AC=23×78=52
Commented by ridwan balatif last updated on 21/Dec/16
thank you sir for your help
thankyousirforyourhelp

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