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Question-9764




Question Number 9764 by tawakalitu last updated on 01/Jan/17
Answered by sandy_suhendra last updated on 01/Jan/17
Commented by sandy_suhendra last updated on 01/Jan/17
OM=OK=5 cm  AM=(1/2)LM=4 cm  BK=(1/2)JK=3 cm  OA=(√(OM^2 −AM^2 ))=(√(5^2 −4^2 ))=3 cm  OB=(√(OK^2 −BK^2 ))=(√(5^2 −3^2 ))=4 cm  r=AB=OB−OA=4−3=1 cm
OM=OK=5cmAM=12LM=4cmBK=12JK=3cmOA=OM2AM2=5242=3cmOB=OK2BK2=5232=4cmr=AB=OBOA=43=1cm
Commented by tawakalitu last updated on 01/Jan/17
Thank you sir. God bless you.
Thankyousir.Godblessyou.

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