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S-1-x-y-R-2-x-2-y-2-1-0-4pi-E-1-1-E-1-1-R-2-t-1-cos-t-sin-t-cos-t-sin-t-S-1-E-1-1-1-is-injective-into-E-1-1-2-can-1-E-1-1-0-4pi-be-continuous-




Question Number 1456 by 123456 last updated on 06/Aug/15
 S^1 ={(x,y)∈R^2 :x^2 +y^2 =1}  ϕ:[0,4π)→E^(1,1) ,E^(1,1) ⊂R^2   ϕ(t)=(1+cos t sin t)(cos t,sin t)  S^1 ∩E^(1,1) ≠∅  1.is ϕ injective into E^(1,1)   2.can ϕ^(−1) :E^(1,1) →[0,4π) be continuous?
S1={(x,y)R2:x2+y2=1}φ:[0,4π)E1,1,E1,1R2φ(t)=(1+costsint)(cost,sint)S1E1,11.isφinjectiveintoE1,12.canφ1:E1,1[0,4π)becontinuous?

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