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sec-3-x-dx-




Question Number 76615 by mhmd last updated on 28/Dec/19
∫sec^3 x dx
sec3xdx
Answered by $@ty@m123 last updated on 28/Dec/19
∫(√(1+tan^2 x)).sec^2 xdx  ∫(√(1+t^2 ))dt  (t/2)(√(1+t^2 ))+(1/2)ln (t+(√(1+t^2 ))) +C  where  t=tan x
1+tan2x.sec2xdx1+t2dtt21+t2+12ln(t+1+t2)+Cwheret=tanx
Answered by john santu last updated on 29/Dec/19
Commented by mhmd last updated on 29/Dec/19
thank you sir
thankyousir
Commented by john santu last updated on 29/Dec/19
your welcome sir
yourwelcomesir

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