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sec-3-xdx-




Question Number 495 by 13/NaSaNa(N)056565 last updated on 25/Jan/15
∫sec^3 xdx
sec3xdx
Answered by prakash jain last updated on 15/Jan/15
tan x=t  sec^2 x dx=dt  sec x=(√(1+t^2 ))  ∫sec^3 x dx=∫(√(1+t^2 ))dt  =(t/2)(√(1+t^2 ))+(1/2)ln ∣t+(√(1+t^2 ))∣+C  =((tan x sec x)/2)+(1/2)ln ∣sec x+tan x∣+C
tanx=tsec2xdx=dtsecx=1+t2sec3xdx=1+t2dt=t21+t2+12lnt+1+t2+C=tanxsecx2+12lnsecx+tanx+C

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