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Show-that-3-5-7-9-2013-1-mod-11-




Question Number 5947 by Yozzii last updated on 07/Jun/16
  Show that 3!^(5!^(7!^(9!^(...2013!) ) ) )  ≡1 (mod 11).
$$ \\ $$$${Show}\:{that}\:\mathrm{3}!^{\mathrm{5}!^{\mathrm{7}!^{\mathrm{9}!^{…\mathrm{2013}!} } } } \:\equiv\mathrm{1}\:\left({mod}\:\mathrm{11}\right). \\ $$

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