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Question Number 8838 by tawakalitu last updated on 31/Oct/16

Show that : e^{i π + 1} = 0

Answered by FilupSmith last updated on 31/Oct/16

do you mean e^{i π} + 1 = 0

e^{i x} = \cos (x) + i \sin (x)

x = π

e^{i π} = (- 1) + i (0)

e^{i π} = - 1

∴ e^{i π} + 1 = (- 1) + 1 = 0

Commented by tawakalitu last updated on 31/Oct/16

God bless you sir .