show-that-f-x-x-is-not-differentiable-at-x-0-where-x-denotes-he-absolute-value-function-

Question Number 73566 by Rio Michael last updated on 13/Nov/19

s h o w t h a t f (x) = ∣ x ∣ i s n o t d i f f e r e n t i a b l e a t x = 0, w h e r e ∣ x ∣

d e n o t e s h e a b s o l u t e v a l u e f u n c t i o n

Commented by Rio Michael last updated on 13/Nov/19

t h a n k s s i r,

b u t w h e n l o o k i n g a t d i f f e r e n t i a b i l i t y

s h o u l d w e t a k e

d e r i v a t i v e s a t x = 0 f r o m b o t h d i r e c t i o n ?

Commented by kaivan.ahmadi last updated on 13/Nov/19

f_{-}^{'} (0) = - 1

f_{+}^{'} (0) = 1

Commented by malwaan last updated on 14/Nov/19

y e s

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