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Question Number 908 by 112358 last updated on 20/Apr/15
Show that for the system of   equations                          x+y+z=3                   2x+2y+2z=6                   3x+3y+3z=9  the general solution is given by                            x=λ+1                            y=μ+1                            z=−λ−μ+1  where λ,μ∈R .
Showthatforthesystemofequationsx+y+z=32x+2y+2z=63x+3y+3z=9thegeneralsolutionisgivenbyx=λ+1y=μ+1z=λμ+1whereλ,μR.
Commented by prakash jain last updated on 21/Apr/15
Only one equation is given  x+y+z=3  Two variable can be independently chosen.  Any value can be chosen for x and y.  If x=λ+1, y=μ+1  x+y+z=3  z=3−x−y=1−λ−μ  λ, μ can be real or complex.  For the general solution λ,μ need not be real.
Onlyoneequationisgivenx+y+z=3Twovariablecanbeindependentlychosen.Anyvaluecanbechosenforxandy.Ifx=λ+1,y=μ+1x+y+z=3z=3xy=1λμλ,μcanberealorcomplex.Forthegeneralsolutionλ,μneednotbereal.

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