Menu Close

Show-that-lim-x-y-0-0-3-x-2-2y-2-does-not-exist-




Question Number 69319 by Joel122 last updated on 22/Sep/19
Show that   lim_((x,y)→(0,0))  (3/(x^2  + 2y^2 ))  does not exist
Showthatlim(x,y)(0,0)3x2+2y2doesnotexist
Commented by Joel122 last updated on 22/Sep/19
I have approached (0,0) along  x−axis, y−axis,  y=x, y = x^2 , y = (√x) and it give same answer +∞  So, why the limit doesn′t exist? Should I   try using different approach?
Ihaveapproached(0,0)alongxaxis,yaxis,y=x,y=x2,y=xanditgivesameanswer+So,whythelimitdoesntexist?ShouldItryusingdifferentapproach?
Commented by MJS last updated on 22/Sep/19
lim=±∞ means it doesn′t exist because  ±∞∉R
lim=±meansitdoesntexistbecause±R
Commented by prof Abdo imad last updated on 23/Sep/19
x=rcosθ and y =(r/( (√2)))sinθ    (x,y)→(0,0)⇒r→0  and lim_((x,y)→(0,0))    (3/(x^2  +2y^2 )) =lim_(r→0)    (3/r^2 ) =+∞  so the limit is infinite
x=rcosθandy=r2sinθ(x,y)(0,0)r0andlim(x,y)(0,0)3x2+2y2=limr03r2=+sothelimitisinfinite
Commented by Joel122 last updated on 23/Sep/19
thank you Sir
thankyouSir

Leave a Reply

Your email address will not be published. Required fields are marked *