Show-that-the-construction-of-the-rectangle-of-minimum-perimeter-when-its-area-is-ab-where-a-AB-and-b-CD-are-given-is-possible-with-ruler-and-compass-

Question Number 3838 by Rasheed Soomro last updated on 22/Dec/15

S h o w t h a t t h e c o n s t r u c t i o n o f

the rectangle of minimum

perimeter when its area is ab

where a = AB and b = CD are given

i s p o s s i b l e w i t h r u l e r a n d c o m p a s s .

Commented by prakash jain last updated on 22/Dec/15

For a given area square has minimum

permeter among rectangles .

side of square = \sqrt{a b}

Commented by Rasheed Soomro last updated on 22/Dec/15

T o S i r P r a k a s h

Q u e s t i o n i s t h e n^{'} t o s h o w t h a t a r e c t a n g l e

c a n b e s q u a r e d w i t h r u l e r a n d c o m p a s s .^{'}

But y o u {d o n}^{'} t n e e d t o d o s o, b e c a u s e i n

a n s w e r i n g s o m e o t h e r q u e s t i o n s y o u h a v e

a l r e a d y p r o v e d t h a t ab c a n b e c o n s t r u c t e d

w h e n a a n d b a r e g i v e n a n d a l s o s q u a r e r o o t

o f a n y n u m b e r \dots

I f a n y b o d y e l s e w a n t s t o t r y, h e c a n .

Commented by prakash jain last updated on 22/Dec/15

Answers to previous question already show

that a b and \sqrt{a b} can be drawn .

Commented by Rasheed Soomro last updated on 22/Dec/15

TH a n K^{S}!