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Show-that-the-curve-defined-by-r-sin2-sin3-0-2pi-0-6pi-is-a-closed-loop-




Question Number 4415 by Yozzii last updated on 22/Jan/16
Show that the curve defined by  r=sin2θ−sin3θ    (0.2π≤θ≤0.6π)  is a closed loop.
$${Show}\:{that}\:{the}\:{curve}\:{defined}\:{by} \\ $$$${r}={sin}\mathrm{2}\theta−{sin}\mathrm{3}\theta\:\:\:\:\left(\mathrm{0}.\mathrm{2}\pi\leqslant\theta\leqslant\mathrm{0}.\mathrm{6}\pi\right) \\ $$$${is}\:{a}\:{closed}\:{loop}.\: \\ $$$$ \\ $$

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