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Simplify-the-following-expression-using-the-laws-of-Boolean-algebra-x-y-y-z-x-z-




Question Number 1047 by 112358 last updated on 23/May/15
Simplify the following  expression using the laws of   Boolean algebra:  (x∧∽y)∨(∽y∧∽z)∨(∽x∧∽z) .
SimplifythefollowingexpressionusingthelawsofBooleanalgebra:(xy)(yz)(xz).
Commented by prakash jain last updated on 24/May/15
∽x∧∽z=∽(x∨z)  ∽y∧∽z=∽(y∨z)  (∽(y∨z))∨(∽(x∨z))=∽((y∨z)∧(x∨z))  =∽((y∧x)∨z)
xz=∽(xz)yz=∽(yz)((yz))((xz))=∽((yz)(xz))=∽((yx)z)

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