Simplify-the-following-expression-using-the-laws-of-Boolean-algebra-x-y-y-z-x-z-

Question Number 1047 by 112358 last updated on 23/May/15

S i m p l i f y t h e f o l l o w i n g

e x p r e s s i o n u s i n g t h e l a w s o f

B o o l e a n a l g e b r a :

(x \land ∽ y) \lor (∽ y \land ∽ z) \lor (∽ x \land ∽ z) .

Commented by prakash jain last updated on 24/May/15

∽ x \land ∽ z =∽ (x \lor z)

∽ y \land ∽ z =∽ (y \lor z)

(∽ (y \lor z)) \lor (∽ (x \lor z)) =∽ ((y \lor z) \land (x \lor z))

=∽ ((y \land x) \lor z)