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sin-1-xdx-




Question Number 132613 by aurpeyz last updated on 15/Feb/21
∫sin^(−1) xdx
$$\int{sin}^{−\mathrm{1}} {xdx} \\ $$
Answered by Dwaipayan Shikari last updated on 15/Feb/21
xsin^(−1) x−∫(x/( (√(1−x^2 ))))dx  =xsin^(−1) x+(√(1−x^2 )) +C
$${xsin}^{−\mathrm{1}} {x}−\int\frac{{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}{dx} \\ $$$$={xsin}^{−\mathrm{1}} {x}+\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:+{C} \\ $$

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