Question Number 141840 by Study last updated on 23/May/21
$${sin}^{\mathrm{2}} \left(\mathrm{360}−{x}\right)−\frac{{cos}\left({x}−\mathrm{180}\right)\centerdot{tan}\left(−{x}\right)\centerdot{sin}\left(\mathrm{90}−{x}\right)\centerdot{cos}\left(\mathrm{360}−{x}\right)}{{sin}\left(\mathrm{180}−{x}\right)}=? \\ $$