sin-2-4x-cos-2-x-2sin-4x-cos-2-x- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 135867 by liberty last updated on 16/Mar/21 sin2(4x)+cos2(x)=2sin(4x)cos2(x) Answered by EDWIN88 last updated on 16/Mar/21 recallcos2x=12+12cos2x⇔[2sin2xcos2x]2+12+12cos2x=4sin2xcos2x(12+12cos2x)4sin22xcos22x+12cos2x+12=2sin2xcos2x+2sin2xcos22x8sin22xcos22x+cos2x+1=4sin2xcos2x+4sin2xcos22x8sin22xcos22x+cos2x+sin22x+cos22x=4sin2xcos2x+4sin2xcos22x Answered by liberty last updated on 17/Mar/21 Answered by MJS_new last updated on 17/Mar/21 usingtrigonometricformulasIget[sinx=s∧cosx=c]−c2(64c2s4−16s2−1)=8c3s(2c2−1)⇒cosx=0⇔★x=nπ−π2∧n∈Z★−(64c2s4−16s2−1)=8cs(2c2−1)thishasnorealsolution Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: please-explain-V-x-F-x-dx-Next Next post: Question-135868 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.